6.3^2+b^2=15.4^2

Solution for 6.3^2+b^2=15.4^2 equation:

6.3^2+b^2=15.4^2

We move all terms to the left:

6.3^2+b^2-(15.4^2)=0

We add all the numbers together, and all the variables

b^2-197.47=0

a = 1; b = 0; c = -197.47;
Δ = b2-4ac
Δ = 02-4·1·(-197.47)
Δ = 789.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{789.88}}{2*1}=\frac{0-\sqrt{789.88}}{2}
=-\frac{\sqrt{}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{789.88}}{2*1}=\frac{0+\sqrt{789.88}}{2}
=\frac{\sqrt{}}{2}
$